python - Numpy using smaller 2D array to map with bigger array with more elements -

i have smaller array as:

a = np.array([2011, 2014, 2015, 2016, 2017]) aval = np.array([14, 10, 35, 40, 45]) 

i have array:

a2 = np.array([2013, 2014, 2015, 2014, 2015, 2016, 2016, 2016, 2017]) 

i want create a2val such that:

arval = np.array([10, 35, 10, 35, 40, 40, 40, 45]) 

so, trying use values in array map elements of a2 , generate extended version of a2val

please note 2011 present in a, 2013 in a2 not in a2 , respectively. can use following suggested in thread:

aval[np.searchsorted(a,a2)] 

but doesn't produce answer looking for.

here 1 way:

>>> aval[np.searchsorted(a, a2[np.nonzero(np.in1d(a2, a))[0]])] array([10, 35, 10, 35, 40, 40, 40, 45]) 

note getting expected indices in default order second array pass searchsorted() should contain common items first array.