python - Creating a new list from 2 lists based on the index return from a third list -

say have following lists (python 3):

numbers = [1,2,3,4,5,6] letters = [a,b,a,b,c,c] state = [false, false, false, false, false, false] 

what looking receive 2 inputs user 2 index positions within range of length of list letters. if case choices correspond matching letters such , (index 0 , 2), there must change in list state false true said positions. afterwards, should create new list depending on new state list, getting index item numbers if element in state false , getting index item list letters if state true:

choice = 0 choice_2 = 2 if letters[choice] == letters[choice_2]:    change state[choice] , state[choice_2] true create fourth list list state , use values numbers , letters in range(len(state)):     if state[i] == true:        element in index[i] of list letters used     else:        element in index[i] of list numbers used 

creating new list such that:

new_list = [a,2,a,4,5,6] 

numbers = [1,2,3,4,5,6] letters = ["a","b","a","b","c","c"] state = [false, false, false, false, false, false]   choice1 = input("enter 1st choice: ") choice2 = input("enter 2nd choice: ")  if letters[choice1] == letters[choice2]:     state[choice1] = (not state[choice1])     state[choice2] = (not state[choice2])  list = []  print state in range(len(state)):     if state[i] == true:         list.append(letters[i])     else:         list.append(numbers[i])  print list 

input:

enter 1st choice: 0 enter 1st choice: 2 

output:

['a', 2, 'a', 4, 5, 6]