recursion - Julia - equivalent of recursive sapply function in R -


i had function in r (onestep below) took argument vector v , returned new vector v output function of input vector. iterated function niter times , kept output vectors of each iteration (which not same length , can end having length 0) in function iterate follows (minimal example) :

onestep = function (v) c(v,2*v) iterate = function (v, niter) sapply(1:niter, function (iter) {v <<- onestep(v)                                                                return(v) } ) 

example :

v=c(1,2,3) iterate(v,3)   [[1]] [1] 1 2 3 2 4 6  [[2]]  [1]  1  2  3  2  4  6  2  4  6  4  8 12  [[3]]  [1]  1  2  3  2  4  6  2  4  6  4  8 12  2  4  6  4  8 12  4  8 12  8 16 24 

i wondering compact , idiomatic way such recursive function returns intermediate results in julia? thoughts? (apologies if trivial new julia)

not sure on compact , idiomatic front, how i'd it

onestep(v) = [v 2*v]  function iterate(v, niter)     results = array(array, niter)     results[1] = onestep(v)     idx = 2:niter         results[idx] = onestep(results[idx - 1])     end     results end  v = [1 2 3] iterate(v, 3) 

Comments

Popular posts from this blog

javascript - Slick Slider width recalculation -

jsf - PrimeFaces Datatable - What is f:facet actually doing? -

angular2 services - Angular 2 RC 4 Http post not firing -