Can I raise and handle exceptions in the same function -

i raising exception , trying handle exception in snippet. raising exception part , handling exception part done in function. wrong so?

import sys  def water_level(lev):     if(lev<10):         raise exception("invalid level!")       print"new level=" # if exception not raised print new level     lev=lev+10     print lev      try:         if(level<10):             print"alarming situation has occurred."     except exception:         sys.stdout.write('\a')         sys.stdout.flush()      else:            os.system('say "liquid level ok"')  print"enter level of tank" level=input() water_level(level) #function call  

the output not handling exception. can explain me why?

it better raise exception in function , catch it when call function function not , error handling independent. , makes code simpler.

your code never reached except clause because if water level low raises exception , jumps out of function , if okay reaches else clause. print statement in try clause never reached because same condition 1 raises exception , 1 jumps out.

your code should that...

import sys import os  def water_level(level):   #just raise exception in function here   if level < 10:     raise exception("invalid level!")    level = level + 10    print("new level=") # if exception not raised print new level   print(level)  #function call print("enter level of tank")  #cast int level=int(input())  try:     #call function in here     water_level(level)  #catch risen exceptions except exception e:     sys.stdout.write('\a')     sys.stdout.flush()      #print exception(verification)     print(e)      print("alarming situation has occurred.") else:     os.system('say "liquid level ok"') 

note corrected other flaws

• import os missing
• you should cast input() number can number comparisions , additions
• try avoid catch least specific exception exception because catch every other exception too.(thats why added print(e)) -> think custom exceptions