go - unable to obtain all permission bits -

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on shell, have file , change permissions of file sudo chmod 4755 <file>. upon calling lstat on file, i'm seeing correct information permissions, has 4755 permission mode.

in golang program, there reason why i'm not getting correct permission mode bits? i'm formatting result fileinfo().mode().perm() incorrectly? upper 3 bits "special"?

thanks help!

short answer: 3 upper bits special , need accessed separately.

long answer: documentation explains 9 (out of 12) least significant bits considered standard unix permissions.

the documentation defines behavior of perm() function calling:

func (m filemode) perm() filemode  perm returns unix permission bits in m.

this means perm not defined return of additional bits looking for.

furthermore, source code shows perm() function masking value returned filemode() 0777 causing initial 3 bits disregarded.

the modesetuid, modesetgid, , modesticky bits (4, 2, , 1 respectively) must each accessed individually constants of filemode type. performing own masks.

in order determine whether sticky bit set, example, (fileinfo().mode() & modesticky) != 0. same applies modesetuid , modsetgid.


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